(2x^2)-(3x^2)=16

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Solution for (2x^2)-(3x^2)=16 equation: 



(2x^2)-(3x^2)=16

We move all terms to the left:

(2x^2)-(3x^2)-(16)=0

We add all the numbers together, and all the variables

-1x^2-16=0

a = -1; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·(-1)·(-16)
Δ = -64
Delta is less than zero, so there is no solution for the equation

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